Last updated at Aug. 3, 2021 by Teachoo

Transcript

Ex 4.3 ,3 Find the roots of the following equations: (i) x โ 1/๐ฅ=3,๐ฅโ 0 x โ 1/๐ฅ=3 (๐ฅ(๐ฅ) โ 1 )/๐ฅ = 3 (๐ฅ^2 โ 1 )/๐ฅ = 3 x2 โ 1 = 3x x2 โ 3x โ 1 = 0 Comparing equation with ax2 + bx + c = 0 So, a = 1, b = โ3, c = โ1 We know that D = b2 โ 4ac D = ( โ3)2 โ 4ร1รโ1 D = 9 + 4 D = 13 Hence, roots to equation are given by x = (โ ๐ ยฑ โ๐ท)/2๐ Putting values x = (โ (โ 3) ยฑ โ13)/(2 ร 1) x = (3 ยฑ โ13)/2 Hence, roots to equation are x = (3 + โ13)/2 or x = (3 โ โ13)/2

Ex 4.3

Ex 4.3, 1 (i)
Deleted for CBSE Board 2022 Exams

Ex 4.3, 1 (ii) Important Deleted for CBSE Board 2022 Exams

Ex 4.3, 1 (iii) Deleted for CBSE Board 2022 Exams

Ex 4.3, 1 (iv) Important Deleted for CBSE Board 2022 Exams

Ex 4.3, 2 (i)

Ex 4.3, 2 (ii)

Ex 4.3, 2 (iii)

Ex 4.3, 2 (iv) Important

Ex 4.3, 3 (i) Important You are here

Ex 4.3, 3 (ii)

Ex 4.3, 4

Ex 4.3, 5

Ex 4.3, 6

Ex 4.3, 7 Important

Ex 4.3, 8 Important

Ex 4.3, 9 Important

Ex 4.3, 10 Important

Ex 4.3, 11

Chapter 4 Class 10 Quadratic Equations (Term 2)

Serial order wise

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.